Error value initialization of which has reference type

List initialization. Aggregate initialization. Static initialization. Zero initialization. Constant initialization. I thought that because of the second constructor that the member variable should be a reference and maybe my second constructor should use a reference parameter too - but then I am a little confused.

Ben: I'm confused by your description. Is the Bar object supposed to be linked to the Foo passed in to the one-argument constructor, such that it sees future changes to that Foo instance?

If so, you'll need a reference parameter in the constructor, and a reference member variable. For the zero-argument case where you want a new Foo instance, you need a non-reference member variable, which the reference can bind to. Luchian's answer shows this in code. BenVoigt thanks for your help, I think I figured this out. I am coming from a C background where class members start as references and need to be initialized.

I have also been reading about the automatic copy constructor. Luchian Grigore Luchian Grigore k 60 60 gold badges silver badges bronze badges. The member order doesn't actually matter -- binding references is one of the few things that's expressly permitted to do with a location that will hold an object in the future but doesn't yet.

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