Where is the extremal kerr isco




















In fact, using the results of Ref. The BL components are the same, since the orbit lies at constant r. The finite terms are needed if the energy and angular momentum are computed directly using the 4-velocity. The limiting frequency shift factor of a photon emitted from the ISCO in the transverse direction, i. By this redshift a distant observer could in principle infer that the orbit coincides with the horizon in the extremal limit.

The 4-velocity of that frame also stretches to an infinite vector and approaches the horizon generator, so the fact that this relative velocity is less than 1 is not inconsistent with the ISCO approaching the speed of light. Now let us examine the distance between the orbits on a BL slice.

Then we have. In conclusion, the orbits both coincide and do not coincide, depending on where they are examined. This is possible since in the extremal limit there is an infinite stretching of the spacetime region outside the horizon along a constant BL time slice 5 5 5 The extremal metric in the neighborhood of the bifurcation surface is written in Ref. For that metric one can show that there are marginally stable orbits at all radii, all with the same energy and angular momentum as that of the extremal ISCO.

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New form of the Kerr solution.



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